Simplify the complex number i^57 as much as possible.?
A-Best: the answer is i
good luck
A: i^4 = 1
i^57 = i(i^4)^14 = i
A: i^57 = i^56 * i = (i²)^23 * i = (-1)^23 * i = -1 * i = -i
A: i^57 = i*(i^56) = i*(i^4)^14 = i*(+1)^14 = i
A: Trust me the answer is i28 times radical 1
